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APIs & raw materials · API (powder)

Assay of an Acidic API by Potentiometric Titration (Ibuprofen, illustrative)

Determines the purity of an acidic API, here ibuprofen, by dissolving it in methanol and titrating the carboxylic acid group with standardised 0.1 M sodium hydroxide, locating the equivalence point potentiometrically.

  • Acid–base potentiometric titration with 0.1 M sodium hydroxide
  • Potentiometric titrator
  • Analytical balance

Reference: Illustrative method modelled on the classic pharmacopoeial titration of ibuprofen with 0.1 M NaOH in methanol. Your monograph may specify an indicator endpoint or a different technique; always follow your approved specification and STP.

PRINCIPLE

Why this method works

Ibuprofen (C₁₃H₁₈O₂, molar mass 206.28 g/mol) has one carboxylic acid group that reacts with sodium hydroxide in a 1 : 1 ratio. As NaOH is added the pH rises slowly and then jumps sharply at the equivalence point. The titrator finds that point from the maximum of the first derivative. Each mL of 0.1 M NaOH is equivalent to 20.63 mg of ibuprofen.

Instruments used

MATERIALS

Reagents & standards

ReagentGrade / specification
0.1 M sodium hydroxideVolumetric solution, standardised against potassium hydrogen phthalate
MethanolAR grade, neutralised if required by the method
pH bufferspH 4.01, 7.00, 9.21 for electrode check
SAMPLE PREPARATION

Preparing the sample

  1. 01

    Check system

    Electrode check and current NaOH molarity.

  2. 02

    Weigh

    Weigh about 0.45 g of sample accurately.

  3. 03

    Dissolve

    Dissolve in 50 mL methanol with stirring.

  4. 04

    Titrate

    Titrate with 0.1 M NaOH to the equivalence point.

  5. 05

    Blank

    Titrate 50 mL methanol alone and subtract.

Procedure

  1. 1Accurately weigh about 0.450 g of the sample into a clean, dry titration beaker.
  2. 2Add 50 mL of methanol and stir until completely dissolved.
  3. 3Immerse the combined pH glass electrode and the burette tip in the solution.
  4. 4Titrate with standardised 0.1 M sodium hydroxide using dynamic dosing, and record the equivalence volume.
  5. 5Carry out a blank titration on 50 mL of methanol and record the blank volume.
  6. 6Analyse in duplicate (or as specified).

Standard preparation

  1. 1No reference standard is needed: the titrant is standardised against a primary standard (potassium hydrogen phthalate) and its molarity is used in the calculation.

Notes for analysts

  • Protect the NaOH from atmospheric carbon dioxide with a soda-lime tube; carbonate makes the equivalence point less sharp.
  • Choose the sample mass so the equivalence point falls at roughly 10–90% of the burette volume.
  • If the method uses a colour indicator instead, results should agree within the method's precision.
TEST CONDITIONS

Method parameters (typical)

Titrant0.1 M NaOH (actual molarity from standardisation)
ElectrodeCombined pH glass electrode suitable for non-aqueous / mixed solvents
Burette20 mL
DosingDynamic, with small increments near the equivalence point
Endpoint evaluationInflection point (maximum of dE/dV)
SolventMethanol, 50 mL
Sample massAbout 0.450 g
BEFORE YOU REPORT

System suitability & sequence

ParameterLimit
Electrode slopeTypically 95–105% of theoretical
Titrant standardisationWithin validity; %RSD of standardisation not more than 0.2%
Titration curveOne clear inflection at the expected volume

Typical sequence

  1. 1Electrode check
  2. 2Blank (methanol) × 1
  3. 3Sample preparation 1
  4. 4Sample preparation 2
CALCULATION

Calculation with a worked example

Assay (% dried basis) = (VS − VB) × (M ÷ 0.1) × 20.63 × 100 ÷ [W × (100 − LOD) ÷ 100]

Where

VS
Volume of NaOH at the sample equivalence point (mL)
VB
Volume of NaOH consumed by the blank (mL)
M
Actual molarity of the NaOH (M)
20.63
mg of ibuprofen equivalent to 1 mL of exactly 0.1 M NaOH (206.28 × 0.1)
W
Weight of sample taken (mg)
LOD
Loss on drying of the sample (%)

Given

W
450.6 mg
VS
21.86 mL
VB
0.05 mL
M
0.10043 M
LOD
0.3%

Working

  1. Net volume = 21.86 − 0.05 = 21.81 mL
  2. Factor = 0.10043 ÷ 0.1 = 1.0043
  3. Ibuprofen found = 21.81 × 1.0043 × 20.63 = 451.88 mg
  4. As-is assay = 451.88 ÷ 450.6 × 100 = 100.28%
  5. Dried weight = 450.6 × (100 − 0.3) ÷ 100 = 449.25 mg
  6. Dried-basis assay = 451.88 ÷ 449.25 × 100 = 100.58%

Assay = 100.6% of C₁₃H₁₈O₂, calculated on the dried basis

ACCEPTANCE CRITERIA

What result passes

  • Typically 98.5% to 101.0% on the dried basis for ibuprofen; use the limit in your approved specification.
METHOD VALIDATION

Validation parameters (ICH Q2(R2))

ParameterTypical requirement
SpecificityTitration is not specific to the API; acidic impurities are titrated too, so purity is controlled together with a related-substances test
AccuracyRecovery with a reference standard typically 99.0–101.0%
PrecisionRepeatability %RSD typically not more than 0.5% (six determinations)
LinearityEquivalence volume against sample mass over about 80–120% of the nominal mass, r ≥ 0.999
RobustnessSolvent volume, stirring speed and dosing parameters
In LimsPulse · Sample Management

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